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Using the theorem, the derivative of \(\ln\big(f(x)\big)\) is \(\frac{f'(x)}{f(x)}\). In this problem, \(f(x) = x^2 +4,\) so \(f'(x) = 2x\). Hence \(\frac{d}{dx}\log\big(x^2 + 4\big) = \frac{2x}{x^2 +4}.\ _\square\)
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